As you know, a return
statement enables a method to return a value to its caller. However, a method
can return only one value each time it is called. What if you need to return two
or more piece of information?
For example:
What if you want to create a method that decomposes a
floating-point number into its integer and fractional parts? To do this requires
that two pieces of information be returned: the integer portion and the
fractional component, this method cannot be written using only a single return
value. The Out modifier solves this problem.
Use out
An out parameter is
similar to a ref parameter with this one exception. It can only be
used to pass a value out of a method.
It is not necessary to give
the variable used as an out parameter an initial value prior to calling
the method. The method will give the variable a value. Furthermore, inside the
method, an out parameter is considered unassigned; that is, it is assumed
to have no initial value. This implies that the method must assign the parameter
a value prior to the method termination. Thus, after the call to the method, an
out parameter will contain a value.
Example
using
System;
using
System.Collections.Generic;
using
System.Linq;
using
System.Text;
namespace
use_out
{
class decomp
{
public int
Twoval(double n, out
double frac)
{
int whole;
whole = (int)n;
frac = n - whole;
return whole;
}
}
class Program
{
static void
Main(string[] args)
{
decomp obj = new
decomp();
int a;
double f;
a =obj.Twoval
(20.125,out f);
Console.WriteLine("integer
part is" + a);
Console.WriteLine("fractional
part is" + f);
Console.Read();
}
}
}
Output
Note: Twoval() method
return two piece of information. First is integer portion of n is
returned as Twoval()’s return value. Second, the fractional portion of
n is passed back to the caller through the out parameter frac.
So the above mention example it is possible for one method to return two
values.
Author-Sayta Prakash
